Point o is the center of the circle. what is the value of x?

Measure of angle x is 34°

Step-by-step explanation:

Given the figure where O is the center of the circle

we have to find the value of x.

∠ORQ=62°   (Given)

By theorem radius from the center of circle is perpendicular to the tangent line.

∴∠OQP=90°

As OR=OQ both are the radii of same circle ∴ ∠ORQ=∠OQR

In ΔOQR by angle sum property of triangle

∠ORQ+∠OQR+∠QOR=180°

62°+62°+∠QOR=180°

∠QOR=56°

In ΔOQP by angle sum property of triangle

∠OPQ+∠OQP+∠QOP=180°

x+90°+56°=180°

x=34°

Hence, measure of angle x is 34°

answer: i don't understand it

step-by-step explanation: sorry

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3