If r = 3 and the sum of 6 terms of the geometric series is 3640, what is the first term?

sum formula = s = a(1-r^n) / (1-r)

3640 = a (1 - 3^6) / (1-3)

3640 = a (1-729) / (-2)

Cross multiply

3640 * (-2) = a * (1-729)

- 7280 = a * (-728)

7280 = a * 728

Dividing by 728

a = 10 : Answer

Hope it will help :)

if you explain the the question more correctly i might be able to answer this better

step-by-step explanation: