Solve the following equality : cos2v=cos40

Take the inverse cosine of both sides.

... arccos(cos(2v)) = arccos(cos(40°))

... 2v = ±40° + k·360° . . . . . for k = any integer

... v = ±20° + k·180° . . . . . . for k = any integer

answer: the two figures are congruent.

step-by-step explanation: they're congruent because figure efgh is reflected across the x and y axis but it was also rotated.

hope it !