Suppose that there are two types of tickets to a show: advance and same-day. advance tickets cost $35 and same-day tickets cost $30 . for one performance, there were 55 tickets sold in all, and the total amount paid for them was $1775 . how many tickets of each type were sold? number of advance ticket sold? number of same day ticket sold?

a = amount of advance tickets sold

s = amount of same-day tickets sold

we know that for that performance 55 were sold in all, thus a + s = 55.

and since we know each a costs 35, then the whole amount sold was 35a, and for all s sold it was then likewise 30a.

the total amount paid for all 55 that day was 1775, thus 35a + 30a = 1775.

how many s were sold? well s = 55 - a.

a = 3.14

b = 18

c = 18/5 or 3.6 or 3 3/5

step-by-step explanation: