Consider the function f(x) = x2 + 3x − 7. find the value of f(x) when x = 3 and select the correct answer below. 5 8 11 18

When x = 3, the function f(x) = x² + 3x − 7 has a value of 11.

To find the value of the function when we are given a certain value of x, we need to substitute the value of x (in this case 3) wherever we see it in the function, and then simplify the function like always.

In this function, x appears 2 times, in x² and 3x. Substituting x = 3, we get:

f(x) = (3)² + 3(3) - 7

Now we simplify using the order of operations. Exponents:

f(x) = 9 + 3(3) - 7

Multiplication

f(x) = 9 + 9 - 7

Addition and subtraction

f(x) = 11

That means that f(x) = 11 when x = 3.

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source