How do i solve #13? (linear equations)

#12:

Assuming that I have those points correct: (1, 5) and (-4, -10), the slope of this line is

5-(-10)

m = = 15/5 = 3

1-(-4)

The line passes thru the origin, so the y-intercept is 0.

So the equation of this line is y = 3x.

I see no marks (points) in the illustration for #13.

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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