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![\bf sin^2(\theta)+cos^2(\theta)=1\implies sin^2(\theta)=1-cos^2(\theta)\\\\ -------------------------------\\\\\\-sin^2(x)=2cos(x)-2\implies -[1-cos^2(x)]=2cos(x)-2 \\\\\\ cos^2(x)-1=2cos(x)-2\implies \stackrel{ax^2+bx+c~form}{cos^2(x)-2cos(x)+1}=0 \\\\\\\ [cos(x)-1][cos(x)-1]=0\implies cos(x)=1\implies \measuredangle x= \begin{cases} 0\\ 2\pi \end{cases}](/tpl/images/0088/1706/4aa52.png)
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