Use the equation and type the ordered-pairs. y = log2 x {(1/ (1, (2, ( ( (16, ? )}

Given the equation

y=

{(1/2,?), (1, ?), (2, ?), (4,?), (8,?), (16, ?)}

Lets start with (1/2, ?)

Ordered pair is (x,y)

In (1/2, ?) , x=1/2 and we need to find out y

y=

Plug in 1/2 for x, y= = = -1

we do the same for all ordered pairs

(1, ?)

Plug in 1 for x, y= = = 0

(2, ?)

Plug in 2 for x, y= = = 1

(4, ?)

Plug in 4 for x, y= = = 2

(8, ?)

Plug in 8 for x, y= = = 3

(16, ?)

Plug in 16 for x, y= = = 4

Ordered pairs are

{(1/2,-1), (1, 0), (2, 1), (4,2), (8,3), (16, 4)}

yes because there is exactly one y value for every x value

for function there can't be more than one value for every x value

it is true

step-by-step explanation:

all the combinations add up i used   calculator