Jared wants to paint his room. the dimensions of the room. are 12 by 15 feet and the walls 9 feet. there are two windows, each with dimensions 6 feet by 5 feet. there are two doors, each with dimensions 30 inches by 6 feet. if a gallon of paint covers about 350 squrae feet. how many gallons of paint will he need to put two coats of paints on the wall

2.26 gallons of the paint will be required.

Step-by-step explanation:

Jared wants to paint his room with dimensions 12 feet × 15 feet × 9 feet.

There are two windows of dimensions (6 feet × 5 feet) and two doors with dimensions (30 inches × 6 feet)

To paint this room we have to exclude the area of windows and doors from the area of walls of the room.

Area of walls = 2(Length + width)Height

                      = 2(12 + 15)9 = 2×27×9

                      = 18×27

                      = 486 feet²

Area of the windows = 2(6×5)

                                   = 60 feet²

Dimensions of doors = 30 inches by 6 feet

                                   = feet by 6 feet

                                   = 2.5 feet by 6 feet

Area of the doors = 2(2.5 × 6)

                             = 30 feet²

Now area of the walls excluding windows and doors = 486 - (60 + 30)

                                                                                        = 486 - 90

                                                                                        = 396 feet²

∵ 350 square feet area is covered by paint = 1 gallon

∴ 1 square feet area will be covered by paint = gallons

∴ 396 feet² area will be covered by the paint =  

                                                                           = 1.131 gallons

This volume of paint is sufficient for one coat so paint required for two coats = 1.131×2 = 2.26 gallons

Therefore, 2.26 gallons of paint will be required.

step-by-step explanation:

i think you should think about the question and not look online.

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.