Can you me ? i think i figured it out but am not sure . you !

Thank you for posting the figure. Without it, I would have thought the parabola has a vertical axis.

For a parabola with a horizontal axis (as in this case), the equation of the parabola is

f(y)=a(y-k)^2+h

where (h,k) is the vertex.

Substituting (h,k)=(2,-4),

f(y)=a(y+4)^2+2(1)

as the equation of the parabola, with the value of "a" yet unknown.

Since we are given that the parabola passes through the point (-3,-3), we can substitute the corresponding x,y values in (1) to solve for a.

f(y)=-3=a(-3+4)^2+2

solve for a

a=(-3-2)/(1^2)=-5

So the equation of the parabola is f(y)=-5(y+4)^2+2

a

b

d

step-by-step explanation:

what is the answer?