Given csc x/cot x = square root of 2 , find a numerical value of one trigonometric function of x.

cscx/cotx = 1/sin(x) / (cos(x)/sin(x)) = 1*sin(x)/(sin(x)*cos(x))=1/cos(x) = sqrt(2)

Now solve for x

1/cos(x) = sqrt(2)

cos(x) = 1/sqrt(2) = sqrt(2)/2

=> x=2k π ± π /4 (general solution)

Thus for x in the first quadrant, x=45 degrees, and

sin(x)=sqrt(2)/2 = 0.70710678

cos(x)=sqrt(2)/2 = 0.70710678

tan(x) = sin(x)/cos(x) = 1

the answer is b.)

< 1=< 2

12.4, 12.387, 12.26, 12.252, 6.241, 6.2, 6.015, 6.009, 1.411, 1.2, 1.056, 1.007, 0.31,   0.13, 0.5, 0.04

step-by-step explanation:

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