The radius of a sphere decreases at a rate of 6 m/sec. find the rate at which the surface area decreases when the radius is 20 m. recall that the surface area of a sphere of radius r is given by s = 4πr2

The radius of the sphere decreases at the rate of 6 m/ sec

That is,

Surface Area of the sphere of radius r is given by

Differentiating with respect to t,

answer: 21$

step-by-step explanation:

$42 / $14 = 3   (ratio 3: 1)

$7 x 3 = $21

your answer is the frist one

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