Atextbook store sold a combined total of 427 physics and history textbooks in a week. the number of history textbooks sold was 79 less than the number of physics textbooks sold. how many textbooks if each type were sold?

Set the equations. Let h = history textbooks, and p = physics textbooks

p + h = 427

p = h + 79

Plug in "h + 79" for "p"

h + 79 + h = 427

Simplify. Combine like terms

2h + 79 = 427

Isolate the h. Do the opposite of PEMDAS. subtract 79 from both sides.

2h + 79 (-79) = 427 (-79)

2h = 348

Isolate the h. Divide 2 from both sides

2h/2 = 348/2

h = 348/2

h = 174

Plug in 174 for h in one of the equations.

p = h + 79

p = 174 + 79

p = 253

History Textbooks = 174

Physics Textbooks = 253

hope this helps

This is a sum and difference problem.

If you don't like system of equations, you can solve this problem doing the following:

Physics books (larger of the two numbers) = (427+79)/2 = 253

History books (smaller of the two numbers) = (427-79)/2=174

Check:

253+174=427 ✔

253-174=79 ✔

from the figure we get,

the x axis shows   the months and,

the y-axis shows the number of satisfied customer.

each line or each cell in upward direction (y-axis) shows 500.

the appropriate scale for the y - axis is: -

a = 2000 customers

b = 4000 customers

c = 6000 customers

d = 8000 customers

e = 10000 customers

f = 12000 customers

g = 14000 customers

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.