Y(y+4)-y squared =6 is a quadratic equation

I hope your question is to find whether y(y+4)-y squared =6 is a quadratic equation or not.

Let's simplify the left side of the equation. So,

y (y + 4) - y²

= y² + 4y - y²

= 4y Since y² and -y² has cancel out.

So, the above equation changes to

4y = 6.

Notice here the square term has vanish.

So, it's not a quadratic equation.

I hope it's helps you!

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

14.3

step-by-step explanation:

add all the numbers together.

9 + 12 + 15 + 16 + 17 + 17 = 86

now, divide 86 by how many numbers we have: 6.

86 / 6 = 14.3