Solve by setting up a system of linear equations with 2 variables and 2 unknowns. there were 130 faculty at a conference. if there were 18 more women than men attending the conference, how many of each gender attended the conference?

Let there are x men and y women.

there were total 130 faculty

so x+y=130(1)

If there were 18 more women than men ,

then x+18=y(2)

plugging value of y from equation (2) in equation (1)

x+x+18=130

2x=112

x=55

y=x+18=55+18=73

so there are 55 men and 73 women

idk i would have to be there to under stand it

step-by-step explanation:

idk i would have to be there to under stand it

answer: 5 17/33 % (to the tenth)

step-by-step explanation:

he guessed: 34.5 pounds

actual weight is 32.7

there for he is off:

34.5 -32.7 = 1.8

32.7 is the 100%

1.8 represents %? of 32.7

therefore:

32.7   - 100%

1.8     -     x%

x= 1.8*100%/32.7% = 18*100%/327%

x=1800%/327%   = (5 165/327)%

to the tenth:

5 17/33 %