If line bd is both the altitude and median of triangle abc then triangle abc is a. obtuse scaleneb. cannot determinec. acute scalned. isosceles

We have a triangle ΔABC, given that BD is both the altitude and median of triangle ΔABC. It means BD⊥AC and AD=DC.

Now we have two Right triangles ΔBDA and ΔBDC such that:-

1. BD = BD (reflexive property)

2. ∡BDA = ∡BDC = 90° (because BD⊥AC; BD is altitude)

3. DA = DC ( because median BD bisects AC into DA=DC)

4. ΔBDA ≡ ΔBDC (Side-Angle-Side congruency of triangles)

5. BA = BC (CPCTC: corresponding parts of congruent triangles are congruent)

In triangle ABC, if AB = BC then we can say that ΔABC is an isosceles triangle.

Hence, option D i.e. Isosceles triangle is the final answer.

isosceles

Step-by-step explanation:

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

i believe the answer is c.