Determine which of the following statements are true if parabola 1 has the equation f(x)=x^2-4x-12 and parabola 2 has a leading coefficient of 1 and zeros at x = 4 and x = -2. check all that apply. a. parabola 1 has a lower minimum than parabola 2. b. parabola 1 crosses the y-axis higher than parabola 2. c. parabola 1 and parabola 2 have the same line of symmetry. d. parabola 1 and parabola 2 have a zero in common.

the correct answers are

Parabola 1 and Parabola 2 have a zero in common.

Parabola 1 has a lower minimum than Parabola 2.

First of all, we have to find Parabola 2. The general formula is

.

It is given that the leading coefficient is 1, then a=1. Putting 4 and -2 into the formula, we have to solve the following system of equations:

Solving it, we find that b=-2 and c=-8

Parabola 2 is given with

Both functions have a minimum because the parabolas located upwardly. The minimum of Parabola 1 is located below the minimum of Parabola 2. You can observe this result in the attached picture, as well. Parabola 1 is given with blue line.

7 ft 6 in means 7 1/2, because 6 in is 1/2 of a foot. 7 ft 8 in means 7 2/3 because 8 in is 2/3 of a foot. 23/3 = 7 2/3. 15/2 = 7 1/2.

23/3   *   15/2   = 57 1/2

step-by-step explanation:

v = 1/3 a^2h

step-by-step explanation:

if the height is 57.7cm and the height of the slant edge is 18.2cm, then the volume is 1/3 a^2h.