Identify the vertex and the axis of symmetry of the parabola. !

We know that the graph goes in units of 1.

We know that the roots are -1 and 4. (Just assume it's accurate and not off by 0.0000000001.)

We can set it up as an equation: -1(x+1)(x-4) = y (I added -1 because there are two parabolas that go through those points on the x-axis, and since this parabola is facing down, I must add a negative a value.

Then multiply (F.O.I.L. - First, Outer, Inner, Last)

x^2 -4x + x - 4 = -(x^2 - 3x - 4) = -x^2 + 3x + 4

Then using -(b/2a) solve for vertex: -(3/-2) = 3/2

Plug 3/2 back into the equation.

-(3/2)^2 + 3(3/2) + 4 = -9/4 + (9/2) + 4 = 25/4

The vertex would be: (3/2, 25/4)

Axis of symmetry would be: x = 3/2

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step-by-step explanation: