Find  the  first  five  terms  of  each  sequence

#11: First term is 2. Formula for the (n+1)th term is (previous term) + 3.

Thus, we have 2, 5, 8, 11, 14, ... This is an arithmetic sequence with common difference 3.

#12 First term is -4. Formula for the (n+1)th term is (previous term) + n^2.

Second term (n=2): -4 + (2^2) = 0

Third term (n=3) : 0+3^2 = 9

Fourth term (n=4): 9 + 4^2 = 25

Fifth term (n=5) : 25 + 5^2 = 50

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .

$15.40 per mile

step-by-step explanation:

you have to round up to 4 because 6 is over 5 so you have to round the 3 up to 4