Aline passes through the point (-2,4) and it’s y-intercept is (0,-6) what is the equation of the line that is perpendicular to the first line and passes through the point (5,-4)

First, lets find the slope intercept form (mx + b = y) of the first line. Slope is found by the equation .

So the slope of the first line is -5. We already know the y-intercept, so we don't need to solve for it. The first equation is -5x -6 = y.

For a line to be perpendicular, its slope must be the opposite reciprocal of the given line. In this case, the perpendicular line would have the slope of 1/5.

We then input the point given into the equation 1/5x + b = y to find b.

1/5(5) + b = -4

1 + b = -4

b = -5

Therefore the equation of the perpendicular line is 1/5x - 5 = y

about 0.75 hours

step-by-step explanation:

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value