The trigonometric ratios sine and secant are reciprocals of each other true or false?

That's FALSE.

It's sine and cosecant that are reciprocals, as are cosine and secant, as well as tangent and cotangent.

The "co" or complementary functions are their corresponding non-complementary function applied to the complementary angle: cos(x) = sin(90-x), that kind of thing.

The non-co functions sine, secant and tangent all increase with increasing angle in the first quadrant. The co functions all decrease.

Since when sine increases its reciprocal decreases, its reciprocal must be one of the co functions, and of course it's cosecant.

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!