Solve: 2|x + 7|−4 ≥ 0 express the answer in set-builder notation. a. {x | 5 < x < 6} b. {x | x ≥ -5} c. {x | x ≤ -9 or x ≥ -5} d. {x | -9 < x < -5}

To solve an absolute inequality first step is to isolate absolute value expression.

Hence remove -4 from the left side. So, add 4 to each sides of the inequality.

2|x + 7|−4 ≥ 0

2|x + 7|−4 +4≥ 0 +4

2|x + 7| ≥ 4 Combine the like terms.

Divide each sides by 2.

|x + 7| ≥2

Next step is to remove the absolute value sign. So,

x + 7≥2 and x+7≤-2.

x≥2-7 and x≤-2-7

x≥-5 and x≤-9

So, the correct choice is C. {x | x ≤ -9 or x ≥ -5}.

The first one is C) {x|x<= -9 or x=> -5 }

The second one is (-infinity, -9] U [-5, infinity)

I just did it

b. 24 mm

step-by-step explanation:

use the pythagorean theorem.

a^2 + b^2 = c^2

a^2 + 7^2 = 25^2

a^2 + 49 = 625

a^2 = 576

a = 24

answer: b. 24 mm

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.