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Mathematics, 15.07.2019 00:00 hotrdks946
Solve open parentheses square root of 6 close parentheses to the 8 x power = 216xβ3. x = β9 x = β3 x = 0 x = 4
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Having a hard time understanding this question (see attachment).
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Solve open parentheses square root of 6 close parentheses to the 8 x power = 216xβ3. x = β9 x = β3...
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