Right triangle abc with right angle c has a hypotenuse of length 10. if ab= 2 cb, what is the length side ac

AB = 10

AB = 2CB

10 = 2CB

CB = 5

10^2 - 5^2 = AC^2

75 = AC^2

AC = sqrt(75)

AC = 5sqrt(3)

In right angle ΔABC, if ∠C is the right angle, then the hypotenuse is AB.

Given that the hypotenuse is 10, therefore AB = 10

AB = 2CB

10 = 2CB

CB = 10 ÷ 2 = 5

Pythagoras' theorem: a² + b² = c²

5² + AC² = 10²

AC² = 10² - 5²

AC² = 75

AC = √75

AC = 5√3

AC = 5√3

4 candies

step-by-step explanation:

7 x 28 = 196

200 - 196 = 4 candies remaining.