Q#3. if cos x = sqrt(2)/2, and 3pi/2 < x < 2pi, what is sin(x + pi/3) q#4. if tan x = 20/21, and pi < x < 3pi/2, what is sin(x + pi/2) q#5. if sec x = -13/5, and 180 < x < 270, find sin(x/2) q#6. if cos x = -3/5, and 90 < x < 180, find sin(x - 60) and you dont have to show work

#3 sin(x) = -sqrt(2)/2 so x = 315 degrees. So we have sin(x+pi/3) = sin(375) = sin(15) which in exact form would be (sqrt(3) -1)/(2sqrt(2))

#4 to find x we take the arctan(20/21) which is approximately 43.6 degrees and add 180 to it since it's in the 3rd quadrant which is 223.6 degrees so we do sin(223.6 + 90) = sin(313.6) which equals -21/29. This can also be done with the pythagorean theorem. -21/29.

#5 13^2 - 5^2 = 12^2. so sin is -12/-13 = 12/13. we take arcsin of that and add 180 and then divide by 2 and take the sin of that and its approximately 3/sqrt(13).

#6 sin is 4/5 so we take arcsin of that and get 143.13 which -60 is 83.13 and we take the sin of that to get 3/10 + 2sqrt(3)/5

Hope this helped :L

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )