Apoint in the figure is selected at random. find the probability that the point will be in the part that is not shaded

Let r be the radius

Area of the shaded part (which is 2 complete circles)

= 2 x πr²

= 2πr²

Area of the unshaded part (which is a square that has a length 2r)

= 2r x 2r

= 4r²

Probability that the point is in the unshaded area

0.4 (nearest tenth)

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3