What is the equaiton of the line that goes through the point (6,-1) and is parallel to the line represented by the equautions y= -5/6x+3?

parallel lines have the same slope

The slope-intercept form of a linear equatio is y=mx+b, where m stands for the "slope of the line" and b stands for the "y-intercept of the line"

They give you the equation y= -5/6x+3 Notice this is already on the slope-intercept form, so in this case the slope is -5/6 and the y-intercept is 3

You want an equation of the line that is parallel to the given line. The slopes must be the same, so m=-5/6

So far we have y=-5/6x + b

We don't have b yet but that can be found using the given point (6,-1) which tells you that "x is 6 when y is -1"

Replace that on the equation y=-5/6x + b and you get

-1 = (-5/6)(6) + b

-1 = -5 +b

4 = b

b = 4

We found b, or the y-intercept

Go back to the equation y = -5/6 x + b and replace this b with the b we just found

y = -5/6x + 4

just needed some points but try socratic