Match the range of the function f(x)=x^2x-1

Appears that you've overlooked the need to share the possible answer choices.

f(x)=x^2x-1 has a parabolic graph with vertex at (0,-1). This is also the location of the vertex. Because the coefficient of x^2 is positive, this graph opens up. Thus, the smallest possible y value here is -1. The range of this function is

[-1, infinity).