Mathematics, 15.07.2019 03:00 juliana211
Given a(-2,1) and b(3,-4)1) find the distance between a and b2) find the midpoint of segment a and b
Answers: 1
![\bf f(x)=-2x^2-5x-7\\\\ -------------------------------\\\\ \cfrac{f(x+h)-f(x)}{h} \\\\\\ \cfrac{[-2(x+h)^2-5(x+h)-7]~~-~~[-2x^2-5x-7]}{h} \\\\\\ \cfrac{[-2(x^2+2xh+h^2)-5(x+h)-7]~~-~~[-2x^2-5x-7]}{h} \\\\\\ \cfrac{\underline{-2x^2}-4xh-2h^2\underline{-5x}-5h\underline{-7}\underline{+2x^2+5x+7}}{h} \\\\\\ \cfrac{-4xh-2h^2-5h}{h}\implies \cfrac{\underline{h}(-4x-2h-5)}{\underline{h}}\implies -4x-2h-5](/tpl/images/0090/9253/5758c.png)
![\bf -------------------------------\\\\ ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{1})\qquad B(\stackrel{x_2}{3}~,~\stackrel{y_2}{-4})\qquad \qquad % distance value d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AB=\sqrt{[3-(-2)]^2+[-4-1]^2}\implies AB=\sqrt{(3+2)^2+(-4-1)^2} \\\\\\ AB=\sqrt{25+25}\implies AB=\sqrt{2\cdot 25} \\\\\\ AB=\sqrt{2\cdot 5^2}\implies AB=5\sqrt{2}\\\\ -------------------------------\\\\ ](/tpl/images/0090/9253/92194.png)
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Given a(-2,1) and b(3,-4)1) find the distance between a and b2) find the midpoint of segment a and b...
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