Asap plz trapezoid jklm is shown on the coordinate plane below: trapezoid jklm on the coordinate plane with ordered pairs at j negative 6, 5, at k negative 3, 5, at l negative 1, 2, at m negative 8, 2.' align='bottom if trapezoid jklm is translated according to the rule (x, y) → (x + 2, y − 6), what are the coordinates of point l'? (1, −4) (−4, −1) (−7, 4) (0, 7)

The coordinate point L was at (-1, 2) before the transformation. After, it would be:

L' = (-1 + 2, 2 - 6)

L' = (1, -4)

The coordinates of point L' are at (1, -4).

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v