How do you write y=3/7x-1 in standard form

The expression in standard form is 7y - 3x  = -7

The standard form of the equation of a line is expressed as Ax + By = C

m is the slope of the line

b is the y-intercept

Given the expression y = 3/7x - 1

Multiply through by 7

7y = 3x - 7

Subtract 3x from both sides

7y - 3x = -7

Hence the expression in standard form is 7y - 3x  = -7

Learn more here: link

if you need just tell me and i will come to the rescue.

step-by-step explanation: