The decay of 601 mg of an isotope is described by the function a(t)= 601e-0.019t, where t is time in years. find the amount left after 34 years. round your answer to the nearest mg. show all of your work for full credit. (5 points)

Put 34 where t is, then evaluate.

... A(34) = 601·e^(-0.019·34) = 601·e^-0.646

... = 601·0.524138

... ≈ 315

The amount left after 34 years is 315 mg.

the answer is a

step-by-step explanation:

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !