Hi is anyone able to answer this data management question? it falls under the unit “probability distribution.” ( reply asap, giving out 10 points)

I assume you have done binomial distribution before.

Binomial distribution applies when

- experiment consists of Bernoulli trials (i.e. each trial has two possible outcomes)

- probability remains known, and constant throughout the trials

- number of trials is known

- all trials are random and independent

The described experiment satisfies all of the above, so binomial distribution is applicable.

Using a pair of FAIR dice, probability of rolling a double-six is

p=(1/6)^2=1/36.

Number of throws

n=20

Number of times double-sixes are rolled

x=2

Using the standard binomial formula

P(2)=C(n,x)p^x (1-p)^(n-x)

=C(20,2)(1/36)^2(35/36)^(20-2)

=(20*19/(1*2))(1/36)^2*(35/36)^18

=0.0882934

Probability of rolling a double, p = 6(1/36) = 1/6

To calculate the probability of rolling at least two doubles (out of 20), we will calculate probabilities of rolling zero or one double.  Then subtract the sum from 1 to get probability of rolling 2,3,4,5…20 doubles.

P(0)=C(20,0)p^(0) (1-p)^(20-0)

=1*(1/6)^0*(5/6)^20

=0.026084

P(1)=C(20,1)p^(1) (1-p)^(20-1)

=20*(1/6)(5/6)^(20-1)

=20*(1/6)(5/6)^19

=0.104336

P(2≤x≤20)

=1-P(0)-P(1)

=1-0.025084-0.104336

=0.86958

the correct answer is a.) bc< mn 5 stars if this you : )

step-by-step explanation: