The graph shows two lines, a and b. a coordinate plane is shown with two lines, a and b, graphed. line a has a slope of negative 1 and crosses the y axis at 5. line b has a slope of positive 1 and crosses the y axis at 3. how many solutions are there for the pair of equations for lines a and b? explain your answer.

There is one/unique solution to the pair of equations for line A and line B.

We know that the equation of a line in slope intercept form is given by:

                     y= mx+b

where m is the slope of the line and b is the y-intercept of the line.

The graph A:

  Line A has a slope of negative 1 and crosses the y axis at 5.

i.e. the slope of line i.e. m= -1

and y-intercept of line i.e. b=5

Hence, the equation of line A is:

              y= -x+5

Graph B:

Line B has a slope of positive 1 and crosses the y axis at 3.

i.e.  m=1

and b=3

Hence, the equation of line B is:

               y=x+3

Now from the graph of these two lines we see that the system of lines intersect at just one point.

       Hence, there is just one solution for the pair of equations.

the correct answer is 1: 2

step-by-step explanation:

hope this your welcome : )

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4