Ageometric sequence has first term 1/9 and common ratio 3. which is the first term of the sequence which exceeds 1000?

(We know this from a=1/9 and r=3)
Simplifying this, we get:


Since we're finding the first term that exceeds 1000, let's set it equal to 1000.


Multiplying both sides by 27




n≈9.2

We have to round n up, since if n=9, the value would be <1000.
Therefore n=10. Substituting n=10,

=2187

Therefore the first term that exceeds 1000 is 2187, and it is the 10th term