Graph y ≥ -x2 + 1. include picture of graph in your answer.

Pls use " ^ " to denote exponentiation:     y ≥ -x^2 + 1

We know that the graph of the parabola y=x^2 opens up and has its vertex at (0,0).  The graph of y= -x^2 is also a parabola, but it opens down.  Finally, the graph of y = -x^2 + 1 is the same as that of the previous graph, except that it's been translated 1 unit UP.

Graph y = -x^2 + 1.  Then shade the entire area above the graph to obtain the graph of   y ≥ -x^2 + 1.

Plug in numbers for x to get an output, y

For example:

When x = 1

y ≥ -1² + 1
y ≥ 1 + 1
y ≥  2
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Graph: see attached picture

hope this helps

1. statement- ca is parallel to db and e is the midpoint of ad reason- given2. statement- reason- alternate interior angles3. statement- de is congruent to ae reason- definition of midpoint4. statement- triangle aec is congruent to triangle deb reason- asa (angle side angle)