Given: t is tangent at b __ ab is diameter. if m /_dpb = 60°, then m angle db =

we know that

1) PD=PB= radius of the circle P

2) initially PDB is an isosceles triangle. because has two sides equals

so

m ∠ DBP=m ∠ PDB

m ∠ DBP+m ∠ PDB+m ∠ DPB=180

m ∠ DBP=[180-60]/2> m ∠ DBP=60

3) if m ∠ DBP=60°

then

the 3 angles are equals

PDB is an equilateral triangle

therefore

the answer is

m ∠ DBP=60°

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step-by-step explanation: