Abasket contains 11 pieces of fruit, 4 apples, 5 oranges, and 2 bananas. jonas takes a piece of fruit at random from the basket, and then beth takes a piece at random. what is the probability that jonas will get an orange and beth will get an apple?

The probability that Jonas will get an orange and Beth will get an apple is:

A basket contains 11 pieces of fruit, 4 apples, 5 oranges, and 2 bananas.

Let A denote the event of Jonas getting an orange.

and B denote the event of Beth getting an apple.

Let P denote the probability of an event.

Hence,

( Since there are 5 oranges out of a total of 11 oranges )

Also,

( Since after removing one orange there will be one less fruit i.e. there will be total 10 pieces of fruit left out of which 4 are apple)

Hence, The required probability is:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.