What is the missing constant term in the perfect square that starts with x^2-16x? pretty stumped on this one. in advance!

You'll have to find a number, in which, when factored, the factors would add up to -16

x^2 - 16x + 64  (for example)
x                -8
x                -8

(x - 8) (x - 8). If you use FOIL, you will get the trinomial again.

64 can be your answer

hope this helps

What are the options