If a field has the perimeter of 1015 and the length is 505 ft what’s the width

The width of the field is 2.5 feet.

The formula for the perimeter is 2 (length) + 2 (width). Since we know the length and perimeter, we can substitute and solve.

2 (505) + 2 (width) = 1015
1010 + 2 (width) = 1015
1010-1010 + 2 (width) = 1015 - 1010
2 (width) = 5
width = 2.5 feet

That means that the width of the field is 2.5 feet.

Answers: the graph is translated down 1 unit and the domain and range of g(x) is the same as the domain and range of f(x).