What is the slope of a line that is perpendicular to the line shown

 a. 3

Step-by-step explanation:

The slope of a line passing through two points (a,b) and (c,d) is given by :-

Then, the slope of a line passing through two points (0,3) and (3,2) is given by :-

Let m be the slope of the line perpendicular to the given line .

We know that the product of two perpendicular lines is -1.

Then , we have

Hence, the  slope of the line perpendicular to the given line  = 3

the 3rd on is correct

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)