Find the solution to the system of equations: x + 3y = 7 and 2x + 4y = 8 1. isolate x in the first equation: 2. substitute the value for x into the second equation: 3. solve for y: 4. substitute y into either original equation: 5. write the solution as an ordered pair: x = 7 – 3y 2(7 – 3y) + 4y = 8 14 – 6y + 4y = 8 14 – 2y = 8 –2y = –6 y = 3 x + 3(3) = 7