Δjkl has j = 7, k = 11, and m∠j = 18°. complete the statements to determine all possible measures of angle k. triangle jkl meets the criteria, which means it is the ambiguous case. substitute the known values into the law of sines: . cross multiply: 11sin(18°) = . solve for the measure of angle k, and use a calculator to determine the value. round to the nearest degree: m∠k ≈ °. however, because this is the ambiguous case, the measure of angle k could also be °.

K = 29°

The triangle is ΔJKL. Therefore,

m∠J = 18°

m ∠ K = ?

j = 7

k = 11

To find m ∠ K we can use sine rule, Therefore,

j / sin 18° = k / sin K

7 / sin 18°  = 11 / sin K

cross multiply

7 sin k  = 11 sin 18°

sin K = 3.39918693812  / 7

sin K = 0.48559813401

K = sin ⁻¹ 0.48559813401

K = 29.0516591712

K ≈ 29°

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the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents

d

step-by-step explanation: