Suppose the first five terms of a sequence are 4,5,9,27,123. how could the next term in the sequence be generated?

the complete question is
Suppose the first five terms of a sequence are 4, 5, 9, 27, 123. How could the next term in the sequence be generated?

A.by adding 3 to the term number, then finding the factorial of the result
B.by finding the factorial of the term number, then adding 3 to the result
C.by adding 4 to the term number, then finding the factorial of the result
D. by finding the factorial of the term number, then adding 4 to the result

The answer is the option
B) by finding the factorial of the term number, then adding 3 to the result.

Explanation:
Finding the factorial of the term number and then adding 3, we would have:
1!+3 = 1+3 = 4
2!+3 = 2*1+3 = 2+3 = 5
3!+3 = 3*2*1+3 = 6+3 = 9
4!+3 = 4*3*2*1+3 = 24+3 = 27
5!+3 = 5*4*3*2*1+3 = 120+3 = 123

find the next term
6!+3=6*5*4*3*2*1+3=723