Given a quadratic function, f(x) = ax 2 + bx + c has a negative leading coefficient and the vertex that has a negative y-coordinate. determine the number of real zeros of the function.2 real zeros1 real zero1 real zero and 1 imaginary zero2 imaginary zeros

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

its 4 because 2 times 2 is 4, if you double the number two you get four