What is the vertex of the absolute value function defined by ƒ(x) = |x - 7| + 1? ( a. (7,1)( b. (-7,-1)( c. (-7,1)( d. (7,-1)

The vertex of function y = |x| is (0; 0).
We have: f(x) = |x - 7| + 1
shift the graph of the function y = |x| 7 units right and 1 unit up. Then the vertex of function f is (7; 1).
Your answer is A. (7; 1)
Look at the picture.

Im not that good with division but i think 5 is -6but dont quote me on thatim not the best in division but thats my answer