When the product of 6 and the square of a number is increased by 5 times the number, the result is 4. select all of the values that the number could be.

The product of 6 and the square of a number is increased by 5 times the number, the result is 4.

Let's represent the number as y

The algebraic expression for the above sentence is written as:

(6 x y²) + 5y = 4

6y² + 5y = 4

The above expression can also be written as:

6y² + 5y - 4 = 0

We have to factorize the above expression to solve for y

6y² - 3y + 8y - 4 = 0

3y (2y - 1) + 4(2y + 1) = 0

(3y + 4)(2y - 1) = 0

Solving for y

3y + 4 = 0

3y = -4

Divide both sides by 3

3y/3 = -4/3

y =

or

2y - 1 = 0

2y = 1

Divide both sides by 2

2y/2 = 1/2

y =

Therefore, the values that the number could be is given as  

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the last choice

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