What is the solution to the equation shown below

x = 3

Option 1 is correct.

Step-by-step explanation:

Given:

First we check restriction on x from equation.

Denominator can't be 0

So,  x-2 ≠0

         x ≠ 2

Inside the square root value always positive.

Therefore, x-2 ≥ 0

                     x ≥ 2

Now simplify the equation.

squaring both sides

x=3 and two are imaginary

Now we take intersection of all two condition and one solution.

x ≠ 2 and x ≥ 2  and x=3

Intersection of all three, x = 3

Hence, The solution of the given equation is 3

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option