Solve the equation in the complex number system.
x^-3 - 1=0.
i know you have to move the 1 over which leaves you with
x^3=1. how do you get rid of the x^3?

To get rid of , you have to take the third root of both sides:

But that won't help you with understanding the problem. It is better to write as a product of 2 polynomials:

From this we know, that is the solution. Another solutions (complex roots) are the roots of quadratic equation.

Ican't do any of the other stuff, but i can get you started. the answer, i believe, is $2.50.

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