What is the equation of the line that is parallel to the line y − 1 = 4(x + 3) and passes through the point (4, 32)? y = –x + 33 y = –x + 36 y = 4x − 16 y = 4x + 16

The given line is in point-slope form. Replace the point values with the new point and you will have your parallel line. Solve for y by adding the opposite of the constant on the left.

y - 32 = 4(x - 4) . . . . point (-3, 1) replaced with point (4, 32)

y = 4x + 16 . . . . . . . add 32 to both sides of the equation and simplify